(9x+4)(2x^2-5x-3)=0

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Solution for (9x+4)(2x^2-5x-3)=0 equation: 


Simplifying
(9x + 4)(2x2 + -5x + -3) = 0

Reorder the terms:
(4 + 9x)(2x2 + -5x + -3) = 0

Reorder the terms:
(4 + 9x)(-3 + -5x + 2x2) = 0

Multiply (4 + 9x) * (-3 + -5x + 2x2)
(4(-3 + -5x + 2x2) + 9x * (-3 + -5x + 2x2)) = 0
((-3 * 4 + -5x * 4 + 2x2 * 4) + 9x * (-3 + -5x + 2x2)) = 0
((-12 + -20x + 8x2) + 9x * (-3 + -5x + 2x2)) = 0
(-12 + -20x + 8x2 + (-3 * 9x + -5x * 9x + 2x2 * 9x)) = 0
(-12 + -20x + 8x2 + (-27x + -45x2 + 18x3)) = 0

Reorder the terms:
(-12 + -20x + -27x + 8x2 + -45x2 + 18x3) = 0

Combine like terms: -20x + -27x = -47x
(-12 + -47x + 8x2 + -45x2 + 18x3) = 0

Combine like terms: 8x2 + -45x2 = -37x2
(-12 + -47x + -37x2 + 18x3) = 0

Solving
-12 + -47x + -37x2 + 18x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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